\(\dfrac{2}{3}+\dfrac{3}{5}=\dfrac{10}{15}+\dfrac{9}{15}=\dfrac{19}{15}\)
\(\dfrac{3}{7}-\dfrac{1}{5}=\dfrac{15}{35}-\dfrac{7}{35}=\dfrac{8}{35}\)
\(\dfrac{1}{5}:\dfrac{3}{4}\cdot\dfrac{5}{7}=\dfrac{1}{5}\cdot\dfrac{4}{3}\cdot\dfrac{5}{7}=\left(\dfrac{1}{5}\cdot\dfrac{5}{7}\right)\cdot\dfrac{4}{3}=\dfrac{1}{7}\cdot\dfrac{4}{3}=\dfrac{4}{21}\)
\(a)\dfrac{2}{3}+\dfrac{3}{5}=\dfrac{10+9}{15}=\dfrac{19}{15}\)
\(b)\dfrac{3}{7}-\dfrac{1}{5}=\dfrac{15-7}{35}=\dfrac{8}{35}\)
\(c)\dfrac{1}{5}:\dfrac{3}{4}.\dfrac{5}{7}=\dfrac{1}{5}:\dfrac{15}{28}=\dfrac{28}{75}\)
`a, 2/3+3/5=10/15 + 9/15 =19/15`
`b,3/7-1/5=15/35 - 7/35 = 8/15`
`c,1/5:3/4xx5/7=1/5 xx4/3 xx 5/7=4/15 xx 5/7 = 4/21`