Ta có:A=2+22+23+...+220
=>2A=2(2+22+23+...+220)
2A=4+23+24+...+221
=>2A-A=(4+23+24+...+221)-(2+22+23+...+220)
A=221-2
A= 2.( 2+ 2+ 3+ 4+ 5+ 6+ 7+8 +9 + 10= 11+ 12+ 13+ 14+15+ 16+ 17+ 18+ 19+ 20)
A=2.211
A= 422
B= 5.(1+ 5+ 2+ 3+ 4+ 5+ 6+ 7+ 8+ 9+..........+30)
B= 5. 470
B= 2350
Ta có:B=1+5+52+53+...+530
=>5B=5(1+5+52+...+530)
5B=5+52+53+...+531
=>5B-B=(5+52+53+...+531)-(1+5+52+...+530)
4B=531-1
=>B=531-1/4
Bài 1:
A=2+22+23+...+220
2A=22+23+...+220+221
A=\(2^{21}-2\)
Vậy ....
Bài 2:
B=1+5+52+...+530
5B=5+52+...+530+531
4B=531-1
B=\(\frac{5^{31}-1}{4}\)
Vậy .....