\(a)22.3-\left(110+7\right):326\)
\(=66-117:326\)
\(=66-\frac{117}{326}\)
\(=\frac{21399}{326}\)
\(b)1+2+3+.....+2019+2010\)
Ta tạm để số 2010 ra ngoài .
Số số hạng của tổng trên là :
( 2019 - 1 ) : 1 + 1 = 2019 ( sh )
Tổng trên là :
\(\left(2019+1\right)\times2019:2=2039190\)
\(\Rightarrow2039190+2010=2041200\)
\(c)64:4+2.52\)
\(=16+104\)
\(=120\)
\(d)2008.213+87.2008\)
\(=2008.\left(213+87\right)\)
\(=2008.300\)
\(=602400\)
\(e)12: \left\{390:\left[500-\left(125+35.7\right)\right]\right\}\)
\(=12:\left\{390:\left[500-370\right]\right\}\)
\(=12:\left\{390:130\right\}\)
\(=12:3=4\)
\(g)33.118-33.18\)
\(=3894-594\)
\(=3300\)
\(h)150-\left[102-\left(14-11\right).2\right]:9\)
\(=150-\left[102-6\right]:9\)
\(=150-96:9\)
\(=150-\frac{32}{33}\)
\(=\frac{4918}{33}\)
\(i)4.52-3\)
\(=208-3\)
\(=205\)
\(a,22.3-\left(110+7\right):326=66-117:326=21399:326\)
b, 1+2+3+...+2019+2020
Số số hạng: 2020
tổng: (1+2020) x 2020 : 2 = 2041210
c,64:4 + 2.52 = 16+104 = 120
d,2008.213 + 87.2008 = 2008.(213 + 87) = 2008. 300 = 602400
e, 12 : {390:[500-(125 + 35.7)]} = 12 : { 390 : [500 - ( 125 + 245 )]} = 12 : [ 390 : (500 - 370)] = 12 : ( 390 : 130 ) = 12 : 3 = 4
g, 33.118 - 33.18 = 33.(118 - 18) = 33.100 = 3300
h, 150 - [ 102 - ( 14 -11 ).2 ] :9 = 150 - ( 102 - 3.2) : 9 = 105 - 96:9 = 1254 : 9
i, 4.52 - 3 = 208 - 3 = 205
Trả lời:
a,\(22-3-\left(110+7\right)\div326\)
\(=19-117+326\)
\(=-98+326\)
\(=228\)
b,\(1+2+3+...+2019+2020\)
\(=\left(2020+1\right)\times\left[\left(2020-1\right)\div1+1\right]\div2\)
\(=2021\times2020\div2\)
\(=2041210\)
c,\(64\div4+2\times52\)
\(=16+104\)
\(=120\)
d,\(2008\times213+87\times2008\)
\(=2008\times\left(213+87\right)\)
\(=2008\times300\)
\(=602400\)
e,\(12\div\left\{390\div\left[500-\left(125+35\times7\right)\right]\right\}\)
\(=12\div\left\{390\div\left[500-\left(125+245\right)\right]\right\}\)
\(=12\div\left[390\div\left(500-370\right)\right]\)
\(=12\div\left(390\div130\right)\)
\(=12\div3\)
\(=4\)
g,\(33\times118-33\times18\)
\(=33\times\left(118-18\right)\)
\(=33\times100\)
\(=3300\)
h,\(150-\left[102-\left(14-11\right)\times2\right]\div9\)
\(=150-\left(102-3\times2\right)\div9\)
\(=150-\left(102-6\right)\div9\)
\(=150-96\div9\)
\(=150-\frac{32}{3}\)
\(=\frac{418}{3}\)
i,
Trả lời:
a,\(22\times3-\left(110+7\right)\div326\)
\(=66-117\div326\)
\(=66-\frac{117}{326}\)
\(=\frac{21399}{326}\)
b,\(1+2+3+...+2019+2020\)
\(=\left(2020+1\right)\times\left[\left(2020-1\right)\div1+1\right]\div2\)
\(=2021\times2020\div2\)
\(=2041210\)
c,\(64\div4+2\times52\)
\(=16+104\)
\(=120\)
d,\(2008\times213+87\times2008\)
\(=2008\times\left(213+87\right)\)
\(=2008\times300\)
\(=602400\)
e,\(12\div\left\{390\div\left[500-\left(125+35\times7\right)\right]\right\}\)
\(=12\div\left\{390\div\left[500-\left(125+245\right)\right]\right\}\)
\(=12\div\left[390\div\left(500-370\right)\right]\)
\(=12\div\left(390\div130\right)\)
\(=12\div3\)
\(=4\)
g,\(33\times118-33\times18\)
\(=33\times\left(118-18\right)\)
\(=33\times100\)
\(=3300\)
h,\(150-\left[102-\left(14-11\right)\times2\right]\div9\)
\(=150-\left(102-3\times2\right)\div9\)
\(=150-\left(102-6\right)\div9\)
\(=150-96\div9\)
\(=150-\frac{32}{3}\)
\(=\frac{418}{3}\)
i,\(4\times52-3\)
\(=208-3\)
\(=205\)
