\(1+2+3+...+2006+2007\)
\(=\left(2007+1\right)\times2007\div2\)
\(=2008\times2007\div2\)
\(=2015028\)
\(68+72+...+124+128+132\)
\(\left(132-68\right)\div4+1=17\)
\(\left(132+68\right)\times17\div2\)
\(=1700\)
Đúng 0
Bình luận (0)
a) 1 + 2 + 3 +...+ 2006 + 2007
= (2007 + 1) x 2007 : 2
= 2008 x 2007 : 2
= 2015028
b) 132 + 128 + 124 +...+ 72 + 68
= (132 - 68) : 4 + 1 = 17
= (132 + 68) x 17 : 2
= 1700
Đúng 0
Bình luận (0)
