Question

a, 11.(x-6)=4.x+11(x thuộc z)

b,/x-3/+1=x

Answer 1

a/ 11.(x - 6) = 4x + 11

=> 11x - 66 = 4x + 11

=> 11x - 4x = 11 + 66

=> 7x = 77

=> x = 11

Vậy x = 11

b/ |x - 3| + 1 = x

=> |x - 3| = x - 1

\(\Rightarrow\orbr{\begin{cases}x-3=x-1\\x-3=-x+1\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x-x=-1+3\\x+x=1+3\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}0=2\left(sai\right)\\2x=4\end{cases}}\)

=> x = 2

Vậy x = 2

Answer 2

\(a)11\cdot(x-6)=4\cdot x+11\)

\(\Rightarrow11x-66=4x+11\)

\(\Rightarrow11x-4x=66+11\)

\(\Rightarrow7x=77\)

\(\Rightarrow x=11\)

\(b)\left|x-3\right|+1=x\)

\(\Rightarrow x-3+1=x\)

\(\Rightarrow x+x=3+1\)

\(\Rightarrow2x=4\Rightarrow x=2\)

P/S : Hoq chắc :>