Các câu hỏi tương tự
A = \(\left(\frac{1}{51}+\frac{1}{52}+\frac{1}{53}+...+\frac{1}{100}\right):\left(\frac{1}{1.2}+\frac{1}{3.4}+....+\frac{1}{99.100}\right)\)
CMR: \(\left(1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{101}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+...+ \frac{1}{102}\right)=\frac{1}{52}+\frac{1}{53}+...+\frac{1}{102}\)
tinh
\(\left(\frac{1}{51}+\frac{1}{52}+\frac{1}{53}+....+\frac{1}{100}\right)\) : \(\left(\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+.....+\frac{1}{99.100}\right)\)
Chứng minh rằng :
\(\left(1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{99}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+...+\frac{1}{100}\right)=\frac{1}{51}+\frac{1}{52}+\frac{1}{53}+\frac{1}{54}+...+\frac{1}{100}\)
Tính:\(\left(\frac{1}{51}+\frac{1}{52}+\frac{1}{53}+\frac{1}{54}+...+\frac{1}{100}\right):\left(\frac{1}{1\cdot2}+\frac{1}{3\cdot4}+\frac{1}{5\cdot6}+...+\frac{1}{99\cdot100}\right)\)
Chứng minh rằng
\(\left(1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{99}\right)-\left(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{100}\right)\)
\(=\frac{1}{51}+\frac{1}{52}+\frac{1}{53}+...+\frac{1}{100}\)
B1:Tính hợp lí
a) \(1-\frac{1}{2}\left(1+2\right)-\frac{1}{3}\left(1+2+3\right)-...-\frac{1}{101}\left(1+2+...+101\right)\)
B2
Chứng minh \(1.3.5....99=\frac{51}{2}.\frac{52}{2}.\frac{53}{2}....\frac{100}{2}\)
Giải nhanh nhé .Mình đag cần gấp .Cảm ơn!
Chứng minh :
\(\left(1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{101}\right)\)\(-\)\(\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+...+\frac{1}{100}+\frac{1}{102}\right)\)\(=\)\(\frac{1}{52}+\frac{1}{53}+...+\frac{1}{100}+\frac{1}{101}+\frac{1}{102}\)
Mik đng cần gấp , giúp mik nha, giải kĩ cho mik nha
A) Chứng tỏ:\(\frac{1}{3}+\frac{1}{31}+\frac{1}{35}+\frac{1}{37}+\frac{1}{47}+\frac{1}{53}+\frac{1}{61}< \frac{1}{2}\)
B)Tìm cặp số nguyên (x,y) sao cho:
\(\left(x-5\right).\left(x-y+1\right)=-23\)