\(A=1+1+1+1-\left(\frac{1}{3}-\frac{1}{15}-\frac{1}{35}-\frac{1}{63}\right)\)
\(A=4+\left(\frac{1}{1.3}-\frac{1}{3.5}-\frac{1}{5.7}-\frac{1}{7.9}\right)\)
\(A=4+\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}\right)\)
\(A=4+\left(1-\frac{1}{9}\right)\)
\(A=4+\frac{8}{9}=\frac{44}{9}\)
Vậy A=44/9