a) \(0,75+\left(\dfrac{-1}{3}\right)-\dfrac{5}{18}=\dfrac{3}{4}+\left(\dfrac{-1}{3}\right)-\dfrac{5}{18}=\dfrac{5}{12}-\dfrac{5}{18}=\dfrac{5}{36}\)
c) \(\dfrac{4}{15}\cdot\dfrac{1}{3}\cdot\dfrac{15}{20}=\dfrac{4}{15}\cdot\dfrac{1}{3}\cdot\dfrac{3}{4}=\dfrac{5}{45}\cdot\dfrac{3}{4}=\dfrac{15}{180}=\dfrac{1}{12}\)
d) \(\left(\dfrac{-1}{9}\right)\cdot\left(\dfrac{15}{22}\right):\left(\dfrac{-25}{9}\right)=\dfrac{-5}{66}:\left(\dfrac{-25}{9}\right)=\dfrac{-5}{66}\cdot\left(\dfrac{9}{-25}\right)=\dfrac{-3}{-110}=\dfrac{3}{110}\)
a) \(0,75\) + \(\dfrac{-1}{3}\) - \(\dfrac{5}{18}\)= \(\dfrac{5}{12}\) - \(\dfrac{5}{18}\) = \(\dfrac{5}{36}\)
b) \(\dfrac{4}{15}\)x \(\dfrac{1}{3}\)x \(\dfrac{15}{20}\)= 4/45 x 15/20 = 1/15
c) -1/9 x 15/22 : -25/9 = -5/66 : -25/9 = 3/110
\(a.0,75+\left(\dfrac{-1}{3}\right)-\dfrac{5}{18}=\dfrac{75}{100}+\left(\dfrac{-6}{18}\right)-\dfrac{5}{18}=\dfrac{3}{4}-\dfrac{11}{18}=\dfrac{5}{36}\\ b.\dfrac{4}{15}.\dfrac{1}{3}.\dfrac{15}{20}=\dfrac{4}{15}.\dfrac{1}{3}.\dfrac{3}{4}=\dfrac{4.1.3}{15.3.4}=\dfrac{1.1.1}{15.1.1}=\dfrac{1}{15}\\ c.\dfrac{-1}{9}.\dfrac{15}{22}:\left(\dfrac{-25}{9}\right)=\dfrac{-1}{9}.\dfrac{15}{22}.\dfrac{-9}{25}=\dfrac{\left(-1\right).15.\left(-9\right)}{9.22.25}=\dfrac{\left(-1\right).3.\left(-1\right)}{1.22.5}=\dfrac{3}{110}\)