Question

99-x/101 + 97-x/103 + 95-x/105 + 93-x/107 = -4 ( 99-x , 97-x ,.. ở trên tử nhá )
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Answer 1

THAM KHẢO :

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Answer 2

\(\dfrac{99-x}{101}+\dfrac{97-x}{103}+\dfrac{95-x}{105}+\dfrac{93-x}{107}=-4\)\(\dfrac{99-x}{101}+1+\dfrac{97-x}{103}+1+\dfrac{95-x}{105}+1+\dfrac{93-x}{107}+1=-4+1+1+1+1\)\(\dfrac{200-x}{101}+\dfrac{200-x}{103}+\dfrac{200-x}{105}+\dfrac{200-x}{107}=0\)\(\left(200-x\right)\left(\dfrac{1}{101}+\dfrac{1}{103}+\dfrac{1}{105}+\dfrac{1}{107}\right)=0\)
mà \(\dfrac{1}{101}+\dfrac{1}{103}+\dfrac{1}{105}+\dfrac{1}{107}\)luôn lớn hơn 0
=> 200-x=0 => x=200