\(9^8\div3^2\)
ta co\(3^2=9\)
\(\Rightarrow9^8\div3^2=9^8\div9^1=97\)
\(9^8:3^2=\left(3^3\right)^8:3^2=3^{24}:3^2=3^{22}\)
98 : 32 = (32)8 : 32
= 32.8 : 32
= 316 : 32
= 316 - 2
= 314 ( = 4782969)
98 : 32
Ta có:
32 = 9
Giữ nguyên 98
Mà 9 = 91
=> 98 : 91
= 97
98 : 32
Ta có:
32 = 9
Giữ nguyên 98
Mà 9 = 91
=> 98 : 91
= 97
98 : 32 = (32)8 : 32 = 316 : 32 = 316-2 = 314
K cho mình nha Trần Thuý An !^^