Question

9¹⁰x8⁴/18⁹

Answer 1

    \(\dfrac{9^{10}\times8^4}{18^9}\)

=  \(\dfrac{9^{10}\times2^{12}}{9^9\times2^9}\)

=  9 \(\times\) 2³

=  9 \(\times\) 8

=    72 

 

Answer 2

\(\dfrac{9^{10}\times8^4}{18^9}\)

\(=\dfrac{\left(3^2\right)^{10}\times\left(2^3\right)^4}{\left(2\times3^2\right)^9}\)

\(=\dfrac{3^{20}\times2^{12}}{2^9\times3^{18}}\)

\(=\dfrac{3^2\times2^3}{1\times1}\)

\(=9\times8=72\)