\((8x - 3)(3x + 2) - (4x + 7)(x + 4) = (4x + 1)(5x - 1)\\ ⇔ 24x^2 + 16x - 9x - 6 - 4x^2 - 16x -7x - 28 = 20x^2 - 4x + 5x - 1\\ ⇔ 20x^2-16x-34 = 20x^2 +x -1\\ ⇔ -16x -34 = x -1\\ ⇔ x = \dfrac{-33}{17}\)
\((8x - 3)(3x + 2) - (4x + 7)(x + 4) = (4x + 1)(5x - 1)\\ ⇔ 24x^2 + 16x - 9x - 6 - 4x^2 - 16x -7x - 28 = 20x^2 - 4x + 5x - 1\\ ⇔ 20x^2-16x-34 = 20x^2 +x -1\\ ⇔ -16x -34 = x -1\\ ⇔ x = \dfrac{-33}{17}\)
Tìm x biết
1,(2x+5)(2x-7)-(-4x-3)^2=16
2,(8x-3)(3x+2)-(4x+7)(x+4)=(2x+1)-(5x-1)
d) (8x-3) (3x 2) - (4x 7) (x 4) = (2x 1) (5x-1)
2. (8x-3) *(3x+2) -4x+7) *(x+4)= (2x+1)* (5x-1)
Tìm x biết : (8x-3)(3x+2)-(4x+7)(x+4)=(2x+1)(5x-1)
các bạn giúp mik bài này vs
5) (4x-5).(x+2)-(x+5).(x-3)-3x^2-x
6) (x-3).(x+7)-(2x-1).(x+2)+x.(x-1)
7) (7x-3).(2x+1)-(5x-2).(x+4)-9x^2+17x
8) -2.(x-7).(x+3)+(5x-1).(x+4)-3x^2-27x
9) (6x-5).(x+8)-(3x-1).(2x+3)-9.(4x-3)
10) (8x-1).(x+7)-(x-2).(8x+5)-11.(6x+1).
1) (x^3 - x^2)- 4x^2 + 8x - 4 = 0
2) 2x^3 - 50x = 0
3) (x + 1) = ( x + 1)(x - 1)
4) ( 3x+1)^2-4(X-3)^2=0
5)(X+3)(X^2-5X+9)-X^3=2X
6) (4X+3)^2-(4X-3)^2-5X-2=0
7)(X-1)^3-(X-3)(X^2+3X+9)-3X(2-X)=5
Tìm x
(2x-1)(x^3-x+1)=2x^3-3x^2+2
(8x-3)(3x+2)-(4x+7)(x+4)=(2x+1)(5x-1)
tìm x biết
a) (6x-3) (2x+4) + (4x-1) (5-3x) = -21
b) 6x (3x+5) - 2x (9x-2) + (17-x) (x-1) + x (x-18) =0
c) (15-2x) (4x+1) - (13-4x) (2x-3) - (x-1) (x+2) + x2=52
d) (8x-3) (3x+2) - (4x+7) (x+4) = (2x+1) (5x-1) - 33
Giải pt sau:
a, 3 - 4x( 25 - 2x ) - 8x2 + x - 300
b, 2( 1 -3x )/5 - 2+ 3x/10 = 7- 3( x + 1)/4
c, 5x + 2 /6 - 8x - 1/3 = 4x + 2/5 - 5
d, 3x + 2/3 - 3x + 1/6 = 2x + 5/3
Help me