888+112+112+888+1
=(888+112)+(112+888)+1
=1000+1000+1
=1000.2+1
=2000+1
=2001
the
\(888+112+112+888+1\)
\(=1000+1000+1\)
\(=2001\)
\(888+112+112+888+1\)
\(=\left(888.2\right)+\left(112.2\right)+1\)
\(=2001\)
Ai thích thì
888 + 112 + 112 + 888 + 1
= 1000 + 1000 + 1
= 2001 + 1
= 2001
\(888+112+112+888+1\)
\(=1000+1000+1\)
\(=2001\)
\(888+112+112+888+1\)
\(=1000+1000+1\)
\(=2001\)
