\(\frac{8}{3}\cdot\frac{2}{5}\cdot\frac{3}{8}\cdot10\cdot\frac{19}{92}=\left(\frac{8}{3}\cdot\frac{3}{8}\right)\cdot\left(\frac{2}{5}\cdot10\right)\cdot\frac{19}{92}=1\cdot4\cdot\frac{19}{92}=4\cdot\frac{19}{92}=\frac{19}{23}\)
\(\frac{8}{3}.\frac{2}{5}.\frac{3}{8}.10.\frac{19}{92}\)
\(=(\frac{8}{3}.\frac{3}{8}).(\frac{2}{5}.10).\frac{19}{92}\)
\(=4.\frac{19}{92}\)
\(=\frac{19}{23}\)
Hok tôt !!!!!!!!!!!!!!!
\(2^{x-3}-3.2^x=-92\)
2^x-3 - 3.2^x = -92 giúp em với mn sắp phải nộp rồi :(
Tìm x
\(\dfrac{1}{4}x-\dfrac{1}{3}=\dfrac{-5}{9}\)
\(2^{x-3}-3.2^x=-92\)
3^(10)+6^(2)/5.3^(8)+20
3^(10)+6^(2)/5.3^(8)+20
\(\frac{3^{10}+6^2}{5.3^8+20}=?\)
{x^2 -[6^2 -( 8^2- 9.7 ) ^3 -7.5 ]^3-5.3}?^3=1
Rút gọn biểu thức 3^(10)+6^(2)/5.3^(8)+20.Giúp mình nha.Thank!!!!!!
A (-6.37*0.4)*2.5
B (-0.125*-5.3)*8
C -2.5*(-4)*(-7.9)
