Question

`(81^20.5^25)/(125^36.9^40)`

Answer 1

`(81^20 . 5^25)/(125^36 . 9^40)`

Answer 2

\(\dfrac{81^{20}.5^{25}}{125^{36}.9^{40}}=\dfrac{\left(9^2\right)^{20}.5^{25}}{\left(5^3\right)^{36}.9^{40}}=\dfrac{9^{40}.5^{25}}{5^{108}.9^{40}}=5^{-83}\)

Answer 3

\(\dfrac{81^{20}.25^{55}}{125^{36}.9^{40}}=\dfrac{\left(9^2\right)^{20}.\left(5^2\right)^{55}}{\left(5^3\right)^{36}.9^{40}}=\dfrac{9^{40}.5^{110}}{5^{108}.9^{40}}=5^2=25\)