Question

81¹¹.3¹⁷

27^10.9⁵

Answer 1

\(\frac{81^{11}.3^{17}}{27^{10}.9^{15}}\)

\(=\frac{3^{44}.3^{17}}{3^{30}.3^{30}}\)

\(=\frac{3^{61}}{3^{60}}\)

\(=3^1=3\)

Answer 2

\(\frac{81^{11}.3^{17}}{27^{10}.9^{15}}=\frac{\left(3^4\right)^{11}.3^{17}}{\left(3^3\right)^{10}.\left(3^2\right)^{15}}=\frac{3^{44}.3^{17}}{3^{30}.3^{30}}=\frac{3^{61}}{3^{60}}=3\)