\(7^{\frac{1}{2}x-5}=343\)
\(7^{\frac{1}{2}x-5}=7^3\)
\(\frac{1}{2}x-5=3\)
\(\frac{1}{2}x=3+5\)
\(\frac{1}{2}x=8\)
\(x=8:\frac{1}{2}\)
\(x=16\)
\(7^{\frac{1}{2}x-5}=343\)
=>\(7^{\frac{1}{2}x-5}=7^3\)
=> \(\frac{1}{2}x-5=3\)
=> \(x=16\)
7 X \(\frac{1}{2}\)hay 7\(\frac{1}{2}\)