Question

7/23*5/29+7/29*18/23-7/29

 

Answer 1

7/23.5/29+7/29.18/23-7/29

=(7.5)/(23.29)+7/29.18/23-7/29

=7/29.5/23+7/29.18/23-7/29.1

=7/29.(5/23+18/23-1)

=7/29.(1-1)

=7/29.0

=0

Answer 2

\(\frac{7}{23}\cdot\frac{5}{29}+\frac{7}{29}\cdot\frac{18}{23}-\frac{7}{29}\)

\(=\frac{7}{29}\cdot\frac{5}{23}+\frac{7}{29}\cdot\frac{18}{23}-\frac{7}{29}\)

\(=\frac{7}{29}\cdot\left(\frac{5}{23}+\frac{18}{23}-1\right)\)

\(=\frac{7}{29}\cdot0\)

\(=0\)