7/23.5/29+7/29.18/23-7/29
=(7.5)/(23.29)+7/29.18/23-7/29
=7/29.5/23+7/29.18/23-7/29.1
=7/29.(5/23+18/23-1)
=7/29.(1-1)
=7/29.0
=0
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\(\frac{7}{23}\cdot\frac{5}{29}+\frac{7}{29}\cdot\frac{18}{23}-\frac{7}{29}\)
\(=\frac{7}{29}\cdot\frac{5}{23}+\frac{7}{29}\cdot\frac{18}{23}-\frac{7}{29}\)
\(=\frac{7}{29}\cdot\left(\frac{5}{23}+\frac{18}{23}-1\right)\)
\(=\frac{7}{29}\cdot0\)
\(=0\)
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