Ta có: 72013+82014+92015=72012\(\times\)7+82012\(\times\)82+92012\(\times\)93
=(74)503\(\times\)7+(84)503\(\times\)64+(94)503\(\times\)729
=(...1)503 \(\times\)7+(...6)503\(\times\)64+(...1)503\(\times\)729
=(...1)\(\times\)7+(...6)\(\times\)64+(...1)\(\times\)729
=(...7)+(...4)+(...9)=(...0)\(⋮\)10
Vậy 72013+82014+92015\(⋮\)10