\(\left(7-x\right)^3+\left(11-7\right)^2=141\\ \left(7-x\right)^3+4^2=141\\ \left(7-x\right)^3+16=141\\ \left(7-x\right)^3=141-16=125=5^3\\ Nên:7-x=5\\ Vậy:x=7-5=2\)
(7-x)3+(11-7)2=141
(7-x)3+42=141
(7-x)3+16=141
(7-x)3=141-16
(7-x)3=125
(7-x)3=53
7-x=5
r đó tự làm =)))