-6x(2x2 - x + \(\dfrac{2}{3}\))
= (-6x) . 2x2 - (-6x) . x + (-6x) . \(\dfrac{2}{3}\)
= -12x3 - (-6x2) + (-4x)
= -12x3 + 6x2 - 4x
\(-6x\left(2x^2-x+\dfrac{2}{3}\right)\)
\(=-12x^3+6x^2-4x\)
-6x(2x2 - x + \(\dfrac{2}{3}\))
= (-6x) . 2x2 - (-6x) . x + (-6x) . \(\dfrac{2}{3}\)
= -12x3 - (-6x2) + (-4x)
= -12x3 + 6x2 - 4x
\(-6x\left(2x^2-x+\dfrac{2}{3}\right)\)
\(=-12x^3+6x^2-4x\)
Bài 2. Tính:
a. (x – 2y)2 b. (2x2 +3)2 c. (x – 2)(x2 + 2x + 4) d. (2x – 1)3
Bài 3: Rút gọn biểu thức
1. (6x + 1)2 + (6x – 1)2 – 2(1 + 6x)(6x – 1) 2. 3(22 + 1)(24 + 1)(28 + 1)(216 + 1)
3. x(2x2 – 3) – x2(5x + 1) + x2. 4. 3x(x – 2) – 5x(1 – x) – 8(x2 – 3)
HEPL ME!
Tìm x, biết:
a) 2(5x-8)-3(4x-5) = 4(3x-4) + 11;
b) 2 x ( 6 x - 2 x 2 ) + 3 x 2 ( x - 4 ) = 8;
c) 2 ( x 3 - 1 ) - 2 x 2 ( x + 2 x 4 ) + ( 4 x 5 + 4 ) x = 6;
d)(2x)2(4x-2)-(x3 -8x2) = 15.
(2x2-7x3-7x2-6x-2) : (2x2+x-1)
aii giúp mình vs ạ :<<
CM các bất phương trình sau luôn dương vs mọi x
1)2x2-2x+17>0
2)-x2+6x-18<0
3)|x-1|+|x|+2>1
Giải PT
a) x3+(x-5)(x+8)= 2x2-37
b)x(x-1)(x+1)(x+2)=24
c)(x2-6x+9)-15(x2-6x+10)=
2x^2 – 6x + 1 = 0
4x^2 – 12x + 5 = 0
2x2 + 5x + 3 = 0
x ^2 + x – 2 = 0
x^ 2 – 4x + 3 = 0
2x^2 + 5x – 3 = 0
x^ 2 + 6x – 16 = 0
tìm x biết
a,x(x-1)+(x+2)(8-x)=1
b.2x2 -6x =0
11,18y2 - 12xy + 2x2
12,(x2+x)2 + 3(x2+x) + 2
13,5x2 - 10xy + 5y2 - 20z2
14,x3 - 9x + 2x2 - 18
15,x2 - 2x - 4y2 - 4y
16,a2 + 2ab + b2 - 2a - 2b + 1
17,x3 - x + 3x2 y + 3xy2 + y3 - y
18,x3 + y3 + z3 - 3xyz
19,x2 + 4x - 5
20,2x2 - 6x - 8
21,x2 - 10xy + 9y2
22,5xz - 5xy - x2 + 2xy - y2
23,(x2 + x + 1) ( x2 + x + 2) - 12
24,(x+1) (x+2) (x+3) (x+4) - 24
25,x3 + 2x2 - 2x - 12