6x - 39 = \(\frac{5628}{28}\)
6x - 39 = 201
6x = 201 + 39
6x = 240
x = 240 : 6
x = 40
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6x - 39 = \(\frac{5628}{28}\)
6x - 39 = 201
6x = 201 + 39
6x = 240
x = 240 : 6
x = 40
(6x- 39).28=5628
[ ( 6x - 39 ) ;3 ] . 28 = 5628
6x-39=5628:28
[ ( 6x - 39 ) : 3 ] . 28 = 5628
Tìm x:
[(6x-39)÷3]÷28=5628
Bài 1.Tìm x
6x-39=5628:28
a,(2x -7) -135=0 b,[(6x-39) :3] . 28=5628
(6x-39).28=5628
tra loi dung nha cac ban
a) [(6x-39):3].28=5628 b)4x3+12=120
c)1500:[(30x+40):x]=30