\(\dfrac{6}{x-3}=\dfrac{7}{x-5}\\ đk:\left\{{}\begin{matrix}x\ne3\\x\ne5\end{matrix}\right.\\ =>6\left(x-5\right)=7\left(x-3\right)\\ =>6x-30=7x-21\\ =>6x-7x=-21+30\\ =>-x=9\\ =>x=-9\left(t/mđk\right)\)
\(\dfrac{6}{x-3}=\dfrac{7}{x-5}\\ 6.\left(x-5\right)=7.\left(x-3\right)\\ 6x-30=7x-21\\ 6x-7x=30-21\\ -x=9\\ x=-9\)