\(6.\left(x+2\right)-3=105\)
\(6.\left(x+2\right)=105+3\)
\(6.\left(x+2\right)=108\)
\(x+2=108:6\)
\(x+2=18\)
\(x=18-2\)
\(x=16\)
Lời giải:
$6(x+2)-3=130-(5^4:25)$
$6x+9=105$
$6x=105-9=96$
$x=96:6=16$
6(x+2)-3=130-(\(5^4:25\))
6(x+2)-3=130-25
6(x+2)-3=105
6(x+2)=105+3=108
x+2=108:6=18
x=18-2
x=16