\(=66\frac{5}{12}+37+25\frac{1}{2}\)
\(\frac{797}{12}+\frac{444}{12}+\frac{51}{2}=\frac{1241}{12}+\frac{306}{12}=\frac{1547}{12}=128\frac{11}{12}\)
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\(66\frac{5}{12}+36\frac{12}{12}+25\frac{12}{24}=66\frac{5}{12}+36+1+25\frac{6}{12}=\left(66+37+25\right)+\left(\frac{5}{12}+\frac{6}{12}\right)=128+\frac{11}{12}=128\frac{11}{12}\)