Đặt A=6+52+53+...+51996
=1+5+52+53+...+51996
=>5A=5+52+53+...+51997
=>5A-A=(5+52+53+...+51997)-(1+5+52+...+51996)
=>4A=51997-1
\(\Rightarrow A=\frac{5^{1997}-1}{4}\)
\(A=6+5^2+5^3+...+5^{1996}\)
\(=1+5+5^2+...+5^{1996}\)
\(\Rightarrow5A=5+5^2+5^3+...+5^{1997}\)
\(\Rightarrow5A-A=4A=5^{1997}-1\)
\(\Rightarrow A=\frac{5^{1997}-1}{4}\)