65 - 4x + 2 = 10000000
=> 65 - 4x + 2 = 1
=> 4x + 2 = 64
=> 4x + 2 = 43
=> x + 2 = 3
=> x = 1
vậy_
\(65-4^{x-2}=1000000^0\)
\(65-4^{x-2}=1\)
\(4^{x-2}=65-1\)
\(4^{x-2}=64\)
\(4^{x-2}=4^3\)
\(x-2=3\)
\(x=3+2\)
\(x=5\)
Vậy x = 5
=))
\(65-4^{x+2}=1000000^0\)
\(65-4^{x+2}=1\)
\(4^{x+2}=65-1=64\)
\(\Rightarrow4^{x+2}=4^4\Rightarrow x+2=4\)
\(\Rightarrow x=4-2=2\)
Vậy \(x=2\)
\(65-4^{x-2}=1\)
\(4^{x-2}=64\)
\(4^{x+2}=4^3\)
\(\Rightarrow4=4\)
\(\Rightarrow x+2=3\)
\(x=1\)