6 : 2 ( 1 + 2 ) = 6 : 2 x 3 = 3 x 3 = 9
6 : 2 ( 1 + 2 ) = 6 : 2 x 3 = 3 x 3 = 9
\(P=\left(\frac{\sqrt{x}-2}{x-1}-\frac{\sqrt{x}+2}{x+2\sqrt{x}+1}\right)\frac{\left(1-x\right)^2}{2}\)
\(P=\left(\frac{\sqrt{x}-2}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}-\frac{\sqrt{x}+2}{\left(\sqrt{x}+1\right)^2}\right)\frac{\left(1-x\right)^2}{2}\)
\(P=\left(\frac{\left(\sqrt{x}-2\right)\left(\sqrt{x}+1\right)-\left(\sqrt{x}+2\right)\left(\sqrt{x}-1\right)}{\left(x-1\right)\left(\sqrt{x}+1\right)}\right)\frac{\left(x-1\right)^2}{2}\)
\(P=\left(\frac{\left(x-\sqrt{x}-2\right)-\left(x+\sqrt{x}-2\right)}{\left(x-1\right)\left(\sqrt{x}+1\right)}\right)\frac{\left(x-1\right)^2}{2}\)
\(P=\frac{2\sqrt{x}}{\left(x-1\right)\left(\sqrt{x}+1\right)}\frac{\left(x-1\right)^2}{2}\)
\(P=\frac{\sqrt{x}\left(x-1\right)}{\sqrt{x}+1}=\sqrt{x}\left(\sqrt{x}-1\right)=x-\sqrt{x}\)
Tìm x , biết :
a)\(x^3+5x^2+8x-4=0\)
b) \(\left(x^2+x\right)\left(x^2+x+1\right)=6\)
\(6\text{ }:\text{ }2\text{ }\left(1\text{ }+\text{ }2\right)=?\)
90% lam sai
giải hệ pt :
\(\hept{\begin{cases}3x^2+6xy+9y^2+\left(x+2y\right)^2\sqrt{x+2y}-3\left(x+2y\right)\sqrt{x+2y}-4\left(x+2y\right)+4\sqrt{x+2y}=0\\\left(\frac{\sqrt[3]{x^2-y^2}}{\sqrt[4]{x}}+\sqrt[4]{\frac{x}{y}}\right)^{2017}+\left(\sqrt[3]{\frac{x}{y}}-\sqrt[4]{\frac{y}{x}}\right)^{2018}=1\end{cases}}\)
tim x
\(\left(x-1\right)+\left(x-2\right)+\left(x-3\right)=2007\)
Tìm x
\(\left(3x-\frac{1}{4}\right)\left(x+\frac{1}{2}\right)=0\)
Tính nhanh :\(\left(9\times8-12-5\times12\right)\times\left(1+2+3+4+5\right)\)
a) \(\left(\frac{2}{x+2}-\frac{4}{x^2+4x+4}\right)\)/\(\left(\frac{2}{x^2-4}+\frac{1}{2x-x}\right)\)
ai làm đúng mình tích cho
Tìm Min, Max của \(A=x\left(x^2-6\right)\) với \(0\le x\le3\)