\(6\frac{1}{2}-3\frac{1}{3}=\frac{13}{2}-\frac{10}{3}=\frac{39}{6}-\frac{20}{6}=\frac{19}{6}=3\frac{1}{6}\)
\(2\frac{1}{2}\cdot3\frac{1}{4}=\frac{5}{2}\cdot\frac{13}{4}=\frac{65}{8}=8\frac{1}{8}\)
\(8\frac{2}{5}:4\frac{2}{7}=\frac{42}{5}:\frac{30}{7}=\frac{42}{5}\cdot\frac{7}{30}=\frac{42\cdot7}{5\cdot30}=\frac{7\cdot7}{5\cdot5}=\frac{49}{25}=1\frac{24}{25}\)