Question

6/11 x =9/2 y = 18/5 z và -x +y +z =-120. tìm x; y ; z

Answer 1

\(\frac{6}{11}x=\frac{9}{2}y=\frac{18}{5}z\) va -x+y+z=-120

\(\left(\frac{6}{11}\right)x=\left(\frac{9}{2}\right)y\Rightarrow x=\left(\frac{9}{2}\right)\left(\frac{11}{6}\right)y=\left(\frac{33}{4}\right)y\)

\(\left(\frac{9}{2}\right)y=\left(\frac{18}{5}\right)z\Rightarrow z=\left(\frac{9}{2}\right)\left(\frac{5}{18}\right)y=\left(\frac{5}{4}\right)y\)

\(\Rightarrow-x+y+z=\left(\frac{-33}{4}\right)y+y+\left(\frac{5}{4}\right)y=-120\)

\(\Rightarrow-6y=-120\Rightarrow y=20;x=165;z=25\)