\(6.x+4.x=2010\)
\(x.\left(6+4\right)=2010\)
\(x.10=2010\)
\(x=2010:10\)
\(x=201\)
Vậy \(x=201\)
\(a,6x+4x=2010\)
\(\Rightarrow x=201\)
\(b,\left(x-4\right)\left(x-7\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-4=0\\x-7=0\end{cases}\Rightarrow\orbr{\begin{cases}x=4\\x=7\end{cases}}}\)
Vậy \(x\in\left\{4;7\right\}\)
a)\(6.x+4.x=2010\)
\(x.\left(6+4\right)=2010\)
\(x.10=2010\)
\(x=2010:10=201\)
b)\(\left(x-4\right).\left(x-7\right)\)
\(\hept{\begin{cases}x-4=0\\x-7=0\end{cases}\Leftrightarrow\hept{\begin{cases}x=4\\x=7\end{cases}}}\)
vậy x= 4 hoặc x=7
a) 6 x X + 4 x X = 2010
( 6 + 4 ) x X = 2010
10 x X = 2010
X = 2010 : 10
X = 201
b) ( X + 4 ) x ( X - 7 ) = 0
X + 4 x X - 7 = 0
làm tương tự cách trên nha
TL :
6 x X + 4 x X = 2010 ( X - 4 ) x ( X - 7 ) = 0
X ( 6 + 4 ) = 2010 \(\Rightarrow\orbr{\begin{cases}X-4=0\\X-7=0\end{cases}\Rightarrow\orbr{\begin{cases}X=4\\X=7\end{cases}}}\)
X x 10 = 2010
X = 2010 : 10
X = 201
Hok tốt :3
\(6\text{ x }x+4\text{ x }x=2010\)
\(x\left(6+4\right)=2010\)
\(x\text{ x }10=2010\)
\(x=2010\text{ : }10\)
\(x=201\)
6.x+4.x=2010
x.(6+4)=2010
x.10=2010
x=2010:10
x=201
vậy x=201
(x-4).(x-7)=0
* x-4=0 * x-7=0
x=0+4 x=0+7
x=4 x=7
vậy x=4 hoặc x=7
vì (x-4).(x-7)=0
=> \(\orbr{\begin{cases}x-4=0\\x-7=0\end{cases}}\)=> \(\orbr{\begin{cases}x=0+4=4\\x=0+7=7\end{cases}}\)=>
Vậy x=7 hoặc x=4
(x-4).(x-7) chứ không pk (x+4).(x-7) nha
và làm theo cách trên cũng sai nha
6.x+4.x=2010
(6+4).x=2010
10x=2010
x=2010:10
x=201
(x-4) (x-7)=0
x=4 và =7
\(\left(x-4\right)\text{ x }\left(x-7\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-4=0\\x-7=0\end{cases}}\) \(\Rightarrow\orbr{\begin{cases}x=0+4\\x=0+7\end{cases}}\) \(\Rightarrow\orbr{\begin{cases}x=4\\x=7\end{cases}}\)
\(\Rightarrow\text{ }x\in\left\{4\text{ ; }7\right\}\)
\(6\text{ x }x+4\text{ x }x=2010\)
\(x\text{ x }\left(6+4\right)=2010\)
\(x\text{ x }10=2010\)
\(x=2010\text{ : }10\)
\(x=201\)
\(\left(x-4\right)\text{ x }\left(x-7\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-4=0\\x-7=0\end{cases}}\) \(\Rightarrow\orbr{\begin{cases}x=0+4\\x=0+7\end{cases}}\) \(\Rightarrow\orbr{\begin{cases}x=4\\x=7\end{cases}}\)
\(\Rightarrow\text{ }x\in\left\{4\text{ ; }7\right\}\)
6 × x + 4 × x = 2010
x × (6+4) = 2010
x × 10 = 2010
x = 2010 : 10
=>x=201
(
(x - 4) × (x - 7) =0
=>x - 4=0 => x - 7 = 0
x=0 x=7
Vậy x = 0;7