Question

6 chia hết(x-1)

Answer 1

Để 6 chia hết cho (x-1)
=>  x = 7 hoặc -5 nhé bạn

Answer 2

ta có: 6 \(⋮\)x -1

=> x - 1 \(\in\)Ư(6) = { -6;-3;-2;-1;1;2;3;6}

=> x \(\in\){ -5;-2;-1;0;2;3;4;7}

vậy: x \(\in\){ -5;-2;-1;0;2;3;4;7}

bạn ủng hộ nha! đúng 100 %.

Answer 3

xl nha mk trả lời thiếu

Answer 4

Ta có: \(6⋮\left(x-1\right)\)

\(\Rightarrow\left(x-1\right)\inƯ\left(6\right)=\left\{-1;1-2;2;-3;3-6;6\right\}\)

*Nếu \(x-1=-1\Rightarrow x=-1+1=0\)

*Nếu \(x-1=1\Rightarrow x=1+1=2\)

*Nếu \(x-1=-2\Rightarrow x=-2+1=-1\)

*Nếu \(x-1=2\Rightarrow x=2+1=3\)

*Nếu \(x-1=-3\Rightarrow x=-3+1=-2\)

*Nếu \(x-1=3\Rightarrow x=3+1=4\)

*Nếu \(x-1=-6\Rightarrow x=-6+1=-5\)

*Nếu \(x-1=6\Rightarrow x=6+1=7\)

\(\Rightarrow x\in\left\{-5;-2;-1;0;2;3;4;7\right\}\)