5x+10+28 chia hết x+2
=> 28 chia hết x+2
=> x+2 thuộc ước 28
\(\left(5x+38\right)⋮\left(x+2\right)\)
\(\Rightarrow\left(5x+10+28\right)⋮\left(x+2\right)\)
\(\Rightarrow28⋮\left(x+2\right)\)
\(\Rightarrow x+2\inƯ\left(28\right)=\left\{1;2;4;7;14;28;-1;-2;-4;-7;-14;-28\right\}\)
\(\Rightarrow x\in\left\{...........\right\}\)
Tính giùm