(5x+1)2 =\(\frac{36}{49}\)
(5x+1)2=\(\frac{6}{7}^2\)
=>(5x+1)=\(\frac{6}{7}\)
5x =\(\frac{6}{7}\)-1=\(\frac{-1}{7}\)
x = \(\frac{-1}{7}\) :5
x= \(\frac{-1}{35}\)
a) (1/2-x/3)2=36/49
b) (3-2/3x)3=-1/64
giúp mình với ạ mình đang cần gắp
\(5x-9=5+3x;2^3+0,5x=1,5;\left(5x+1\right)^2=\dfrac{36}{49};\left(\dfrac{-3}{81}\right)^x=-27;2^{x-1}=16\)
Tìm x,y: (5x+1)^2=36/49=(2y-1)^3
(x-2/9)^3=(2/3)^6=(y/3)^2
(8x-1)^2y+1=5^2y+1 (với y thuộc N)
Tìm x, biết:
a) ( 5x+1)^2+36/49
b) (x-2/9)^3=(2/3)^6
c) (8x-1)^2n+1=5^2n+1
mong mọi người giúp mình
1) tìm x
a) ( x . 1/3 ) 2 = 1/36
b) ( 5x + 1 ) 2 = 36/49
c) ( x - 2/9 ) 3 = ( 2/3 ) 6
Tìm x biết
(-3/4)^3x -1= 256/81
(5x+1) ^2 =36/49
(X-2/9)^3= (2/6)^6
(8x -1)^2n+1 = 5^2n +1
(5x+1)2 = 36/49
(x-2/9)3 = (2/3)6
(8x-1)2n+1= 52n+1
Tìm x biết :
a) (5x+1)mũ 2 =36/49
b)5 mũ x nhân 5 mũ 3 mũ 2 = 625
c) (x-2/9)mũ 3 = (2/3) mũ 6
d)3 mũ x+1 =9 mũ x
MÌNH ĐANG CẦN GẤP. TRẢ LỜI NHANH;ĐÚNG;ĐẦU TIÊN MÌNH TRẢ 5 TICK
Tifm x,y biết:
a (5x+1)2=36/49
b (x-2/9)3=2/36
c (8x-1)2x+1-52x +1
d (x-3,5)2+(y-1/10)4<0
