(5x+1)^2 = 36/49
5x+ 1 = 6/7
5x = -1/7
x = -1/35
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(5x+1)^2 = 36/49
5x+ 1 = 6/7
5x = -1/7
x = -1/35
(5x+1)^2=36/49
gia tri x thoa man (5x + 1 )^2=36/49
tìm x, biết:
(5x+1)^2=36/49
\(5x-9=5+3x;2^3+0,5x=1,5;\left(5x+1\right)^2=\dfrac{36}{49};\left(\dfrac{-3}{81}\right)^x=-27;2^{x-1}=16\)
tìm x biết: (5x+1)2 = 36/49
\(\left(5x+1\right)^2=\frac{36}{49}\)
Tìm x biết:
(5x + 1)2 = 36/49
(5x+1)²=36/49
(5x+1)2=36/49
b, (x-2/9)3=2/3