\(\left|5x-4\right|=\left|x-2\right|\)
\(\Leftrightarrow\orbr{\begin{cases}5x-4=2-x\\5x-4=x-2\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}6x=6\\4x=2\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=1\\x=\frac{1}{2}\end{cases}}\)
Vậy \(x\in\left\{1;\frac{1}{2}\right\}\)
\(\left|5x-4\right|=\left|x-2\right|\)
\(\Rightarrow\orbr{\begin{cases}5x-4=x-2\\5x-4=-\left(x-2\right)\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}5x-x=-2+4\\5x+x=2+4\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}4x=2\\6x=6\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{1}{2}\\x=1\end{cases}}\)
Vậy,...........
\(\left|5x-4\right|=\left|x-2\right|\)
Th1 : \(5x-4=x-2\)
\(\Leftrightarrow5x-x=-2+4\)
\(\Leftrightarrow4x=2\)
\(\Leftrightarrow x=\frac{1}{2}\)
Th2 : \(5x-4=2-x\)
\(\Leftrightarrow5x+x=2+4\)
\(\Leftrightarrow6x=6\)
\(\Leftrightarrow x=1\)
Vậy .....
( Chú ý : ta chỉ xét hai trường hợp cùng dấu và trái dấu ).
