Question

(5x-3)(4-2x)=0 tìm x

Answer 1

\(\left(5x-3\right)\left(4-2x\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}5x-3=0\\4-2x=0\end{matrix}\right.\)         \(\Rightarrow\left[{}\begin{matrix}5x=3\\2x=4\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{5}\\x=2\end{matrix}\right.\)       Vậy \(x\in\left\{\dfrac{3}{5};2\right\}\)

Answer 2

\(\left[{}\begin{matrix}\left(5x-3\right)=0\\\left(4-2x\right)=0\end{matrix}\right.\)

\(\left[{}\begin{matrix}5x=0+3\\2x=4-0\end{matrix}\right.\)

\(\left[{}\begin{matrix}5x=3\\2x=4\end{matrix}\right.\)

\(\left[{}\begin{matrix}x=3\div5\\x=4\div2\end{matrix}\right.\)

\(\left[{}\begin{matrix}x=\dfrac{3}{5}\\x=2\end{matrix}\right.\)

Answer 3

đừng chép mạng, tự làm đi ạ