Đặt \(a=\frac{1}{4453};b=\frac{1}{1997}\)ta có :
\(5\frac{6}{4453}\cdot\frac{1}{1997}-\frac{2}{1997}\cdot2\frac{3}{4453}\)
\(=\left(5+6a\right)\cdot b-2b\left(2+3a\right)\)
\(=5b+6ab-4b-6ab\)
\(=b=\frac{1}{1997}\)
\(F=5\frac{6}{4453}.\frac{1}{1997}-\frac{2}{1997}.2\frac{3}{4453}\)
\(F=5\dfrac{6}{4453}.\dfrac{1}{1997}-\dfrac{2}{1997}.2\dfrac{3}{4453}\)
rút gọn bằng cách thay số bằng chữ
\(\frac{x-1991}{9}+\frac{x-1993}{7}+\frac{x-1995}{5}+\frac{x-1997}{3}+\frac{x-1999}{1}=\frac{x-9}{1991}+\frac{x-7}{1993}+\frac{x-5}{1995}+\frac{x-3}{1997}+\frac{x-1}{1999}\)
Giải phương trình
\(\frac{x+1}{2003}+\frac{x+3}{2001}+\frac{x+5}{1999}=\frac{x+7}{1997}+\frac{x+9}{1995}+\frac{x+11}{1993}\)
Giải phương trình
\(\frac{x+1}{2003}+\frac{x+3}{2001}+\frac{x+5}{1999}-\frac{x+7}{1997}-\frac{x+9}{1995}-\frac{x+11}{1993}=0\)
tìm x
\(\frac{x-1}{2006}+\frac{x-10}{1997}+\frac{x-19}{1988}=3\)
Tìm x bt
\(\frac{x-1}{2006}+\frac{x-10}{1997}+\frac{x-19}{1988}=3\)
Giải phương trình : \(\frac{x+5}{1999}+\frac{x+7}{1997}=\frac{x+9}{1999}+\frac{x+11}{1993}\)
tìm x biết
\(\frac{x-1}{2006}+\frac{x-10}{1997}+\frac{x-19}{1998}=3\)
