5\(\dfrac{5}{27}\)-\(\dfrac{5}{27}\)= 5+\(\dfrac{5}{27}\)-\(\dfrac{5}{27}\)= 5+( \(\dfrac{5}{27}\)-\(\dfrac{5}{27}\))= 5+0=5
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5\(\dfrac{5}{27}\)-\(\dfrac{5}{27}\)= 5+\(\dfrac{5}{27}\)-\(\dfrac{5}{27}\)= 5+( \(\dfrac{5}{27}\)-\(\dfrac{5}{27}\))= 5+0=5