\(\dfrac{-5}{7}\cdot\dfrac{2}{11}+\dfrac{-5}{7}\cdot\dfrac{9}{11}+\dfrac{5}{7}=\dfrac{5}{7}\cdot\dfrac{-2}{11}+\dfrac{5}{7}\cdot\dfrac{-9}{11}+\dfrac{5}{7}\cdot1=\dfrac{5}{7}\cdot\left(\dfrac{-2}{11}+\dfrac{-9}{11}+1\right)=\dfrac{5}{7}\cdot0=\dfrac{0}{7}=0\)
Đúng 2
Bình luận (0)
-5/7 x (2/11 + 9/11 ) + 5/7
=-5/7 x 1 + 5/7
=0
Đúng 4
Bình luận (0)
