\(\left(\frac{5}{7}-y\right)\cdot\frac{14}{5}=\frac{7}{10}+\frac{1}{2}=\left(\frac{5}{7}-y\right)\cdot\frac{14}{5}=\left(\frac{5}{7}-y\right)\cdot\frac{14}{5}=\frac{6}{5}\)\(\frac{6}{5}\)
\(=>\frac{5}{7}-y=\frac{6}{5}\) / \(\frac{14}{5}=\frac{5}{7}-y=\frac{3}{7}=\frac{5}{7}-\frac{3}{7}=\frac{2}{7}\)
\(=>y=\frac{2}{7}\)