\(\frac{5}{6}\cdot x+\frac{2}{3}\cdot\left(\frac{3}{5}\cdot x-\frac{6}{5}\right)=\frac{2}{9}-\frac{1}{2}\)
\(\Rightarrow\frac{5}{6}\cdot x+\frac{2}{3}\cdot\frac{3}{5}\cdot x-\frac{2}{3}\cdot\frac{6}{5}=-\frac{5}{18}\)
\(\Rightarrow\frac{5}{6}\cdot x+\frac{2}{5}\cdot x-\frac{4}{5}=-\frac{5}{18}\)
\(\Rightarrow x\cdot\left(\frac{5}{6}+\frac{2}{5}\right)=-\frac{5}{18}+\frac{4}{5}\)
\(\Rightarrow x\cdot\frac{37}{30}=\frac{47}{90}\)
\(\Rightarrow x=\frac{47}{90}\div\frac{37}{30}\)
\(\Rightarrow x=\frac{47}{111}\)
Vậy \(x=\frac{47}{111}\)
