Đặt \(A=\frac{5}{6}+\frac{5}{12}+\frac{5}{20}+...+\frac{5}{132}\)
\(A=\frac{5}{2.3}+\frac{5}{3.4}+\frac{5}{4.5}+...+\frac{5}{11.12}\)
\(A=5\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{11}-\frac{1}{12}\right)\)
\(A=5\left(\frac{1}{2}-\frac{1}{12}\right)\)
\(A=5\times\frac{5}{12}\)
\(A=\frac{25}{12}\)
=\(\frac{5}{6}\)+ \(\frac{5}{12}\)+ ...+ \(\frac{5}{132}\)
= \(\frac{5}{2.3}\)+ \(\frac{5}{3.4}\)+ ...+ \(\frac{5}{11.12}\)
= \(\frac{5}{2}\)- \(\frac{5}{3}\)+ \(\frac{5}{3}\)- \(\frac{5}{4}\)+ ...+ \(\frac{5}{11}\)- \(\frac{5}{12}\)
= \(\frac{5}{2}\)- \(\frac{5}{12}\)
= \(\frac{25}{12}\)
\(\frac{5}{6}+\frac{5}{12}+\frac{5}{20}+...+\frac{5}{132}\)
\(=\frac{5}{2.3}+\frac{5}{3.4}+\frac{5}{4.5}+...+\frac{5}{11.12}\)
\(=5\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{11}-\frac{1}{12}\right)\)
\(=5\left(\frac{1}{2}-\frac{1}{12}\right)\)
\(=5\cdot\frac{5}{12}=\frac{25}{12}\)