5 x 5 x 5 x 5 x (568 : 4 - 45 : 4) x X = 0
Vì \(\hept{\begin{cases}5x5x5x5\ne0\\568:4-45:4\ne0\end{cases}\Rightarrow5x5x5x5x\left(568:4-45:4\right)\ne0}\)
=> X = 0
5 x 5 x 5 x 5 x (568 : 4 - 45 : 4) x X = 0
Vì \(\hept{\begin{cases}5x5x5x5\ne0\\568:4-45:4\ne0\end{cases}\Rightarrow5x5x5x5x\left(568:4-45:4\right)\ne0}\)
=> X = 0
Tính
a) 568 - { 5 [ 143 - ( 4 - 1 ) 2 ] + 10 } : 10
b) 102 - [ 60 : ( 56 : 54 - 3 x 5 ) ]
Tìm x, biết:
a) (x – 45).27 = 0
b) 45.(2x – 4).13 = 0
c) (x – 3).(x – 5) = 0
Tim x: 6^2-(x+3)=45
125-5.(3x-1)=5^5.5^3
4^x+1+4^0=65
70-5.(x-3)=5.3^2
1, 72-3./x+1/=9
2, 17-(43-/x/)=45
3, 3/x-1/-5=7
4, -12.(x-5)+7.(3-x)=5
5, (x-2) . (x+4)=0
6, (x-2).(x+15)=0
7, (7-x).(x+19)=0
8, -5<x<1
9, /x/<3
10, (x.3).(x-5)<0
Tìm x :
a) 15 . x + 19 = 75 : 73
b) [ 45 + ( 50 - 20 ) ] . x = 103 . 15
c) ( 2x -1 )4 = 81
d) ( x : 23 + 45 ) . 67 = 8911
e) ( 1 + 52 + 54 + 56 + 58 ) . x = 52 + 54 +56 + ... + 510
568-{5[143-(4-1)2]+10}:10
Bài 1: Tìm x
1/(2.x-5)+17=6
2/10-2.(4-3x)=-4
3/-12+3.(-x+7)=-18
4/24:(3.x-2)=-3
5/-45:5.(-3-2.x)=3
6/x.(x+7)=0
7/(x+12).(x-3)=0
8/(-x+5).(3-x)=0
9/x.(2+x).(7-x)=0
10/(x-1).(x+2).(-x-3)=0
568 - { 5 [ 143-(4-1)]2 +10} :10