\(50\%x+\frac{2}{3}x=x+4\)=> \(\frac{1}{2}x+\frac{2}{3}x-x=4\)=> \(\frac{1}{6}x=4\)=> \(x=24\)
\(\Rightarrow\frac{1}{2}x+\frac{2}{3}x=x+4\)
\(\Rightarrow\frac{7}{6}x-x=4\)
\(\Rightarrow\frac{1}{6}x=4\)
\(\Rightarrow x=4:\frac{1}{6}\)
\(\Rightarrow x=4\cdot6\)
\(\Rightarrow x=24\)
\(50\%x=\frac{1}{2}x\)
Ta có :
\(\frac{1}{2}x+\frac{2}{3}x=x+4\)
\(\frac{1}{2}x+\frac{2}{3}x-x=4\)
\(=>\frac{1}{6}x=4\)
\(x=\frac{4}{\frac{1}{6}}\)
\(x=24\)