a) 5.(x-7)=0
=> x-7 = 0
x = 7
b) 34.(2x-6)=0
=> 2x -6 = 0
2x = 6
x = 3
5 (x - 7) = 0
=> x - 7 = 0
=> x = 7
34 (2x - 6) = 0
=> 2x - 6 = 0
=> 2x = 6
=> x = 3
5 (x - 7) = 0
<=> x-7=0
<=> x=7
34 (2x - 6) = 0
<=> 2x-6=0
<=> 2x=6
<=> x=3
a, 5(x-7)=0
=> x-7 = 0
x=7
b,34(2x-6)=0
=>2x-6=0
2x=6
x=3
a)\(5\left(x-7\right)=0\)
\(\Rightarrow x-7=0\)
\(\Rightarrow x=7\)
b)\(34\left(2x-6\right)=0\)
\(\Rightarrow2x-6=0\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=3\)
5 (x - 7) = 0
x - 7 = 0 : 5
x - 7 = 0
x = 0 + 7
x = 7
34 (2x - 6) = 0
2x - 6 = 0 : 34
2x - 6 =0
2x =0+6
2x =6
x =6:2
x =3
x - 7 = 5 x 0= 0
x = 0 + 7
x = 7
34 .(2.x - 6) = 02.x - 6 = 34 . 0 = 0
2.x = 0 + 6 =6
x = 6 : 2
x = 3
k mình nha!!! mình đang cần điểm hỏi đáp!!!
a) \(5\left(x-7\right)=0\)
\(x-7=0\)
\(\Rightarrow x=7\)
b) \(34.\left(2x-6\right)=0\)
\(2x-6=0\)
\(2x=6\)
\(\Rightarrow x=3\)
5.(x-7)=0
=> x - 7 = 0
x = 7
phần cn lại tự lm ik
34(2 x-6)=0
2x-6=0:34
2 x-6=0
2 x=0+6
2 x=6
X= 6:2
X= 3
\(5\cdot\left(x-7\right)=0\)
\(\Rightarrow x-7=0\)
\(\Rightarrow x=0+7\)
\(\Rightarrow x=7\)
Vậy \(x=7\)
\(34\cdot\left(2x-6\right)=0\)
\(\Rightarrow2x-6=0\)
\(\Rightarrow2x=0+6\)
\(\Rightarrow2x=6\)
\(x=6:2\)
\(x=3\)
Vậy \(x=3\)
\(5.\left(x-7\right)=0\)
\(\Rightarrow x-7=0\)
\(\Rightarrow x=7\)
Vậy \(x=7\)
\(32.\left(2x-6\right)=0\)
\(2x-6=0\)
\(2x=6\)
\(x=3\)
Vậy \(x=3\)
5·(x−7)=0
⇒x−7=0
⇒x=0+7
⇒x=7
Vậy x=7
34·(2x−6)=0
⇒2x−6=0
⇒2x=0+6
⇒2x=6
x=6:2
x=3
Vậy x=3
\(5\left(x-7\right)=0\)
\(x-7=0\)
\(x=0+7\)
\(\Rightarrow x=7\)
\(34\left(2x-6\right)=0\)
\(2x-6=0\)
\(2x=0+6\)
\(2x=6\)\(x=6:2\Rightarrow x=3\)
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