Question

5 và 1/3 + 3 và 7/17 - 1 và 7/17 + 4 và 2/3

Answer 1

\(5\dfrac{1}{3}+3=\dfrac{16}{3}+3=\dfrac{25}{3}\\ \dfrac{7}{17}-1\dfrac{7}{17}+4\dfrac{2}{3}=\dfrac{7}{17}-\dfrac{24}{17}+\dfrac{14}{3}=\dfrac{14}{3}-1=\dfrac{11}{3}\)

Answer 2

\(5\dfrac{1}{3}+3\dfrac{7}{17}-1\dfrac{7}{17}+4\dfrac{2}{3}\)

= \(\dfrac{16}{3}+\dfrac{58}{17}-\dfrac{24}{17}+\dfrac{14}{3}\)

= \(\dfrac{16}{3}+\dfrac{14}{3}+\dfrac{58}{17}-\dfrac{24}{17}\)

= \(\dfrac{30}{3}+\dfrac{34}{17}\)

= 10 + 2

= 12