Question

5) Tính tích B = ( 1-\(\frac{1}{2010}\)) x (1-\(\frac{2}{2010}\)) x ( 1-\(\frac{3}{2010}\)) x .... x ( 1- \(\frac{2011}{2010}\))

Answer 1

\(B=\left(1-\frac{1}{2010}\right)x\left(1-\frac{2}{2010}\right)x\left(1-\frac{3}{2010}\right)x...x\left(1-\frac{2011}{2010}\right)\)

\(B=\left(1-\frac{1}{2010}\right)x\left(1-\frac{2}{2010}\right)x\left(1-\frac{3}{2010}\right)x....x\left(1-\frac{2010}{2010}\right)x\left(1-\frac{2011}{2010}\right)\)

\(B=\left(1-\frac{1}{2010}\right)x\left(1-\frac{2}{2010}\right)x\left(1-\frac{3}{2010}\right)x...x\left(0\right)x\left(1-\frac{2011}{2010}\right)\)

\(B=0\)

Answer 2

Phúc 6A phải k

Answer 3

xét các thừa số tích B có: \(1-\frac{2010}{2010}=0\)

Nên B = 0

Answer 4

\(B=0\)