\(4x^3+15=47\)
\(\Leftrightarrow4x^3=32\)
\(\Leftrightarrow x^3=8\)
\(\Leftrightarrow x=2\)
\(4\cdot2^x-3=125\)
\(\Leftrightarrow4\cdot2^x=128\)
\(\Leftrightarrow2^x=32\)
\(\Leftrightarrow2^x=2^5\)
\(\Leftrightarrow x=5\)
4x3 + 15 = 47
=> 4x3 = 47 - 15 = 32
=> x3 = 32 : 4 = 8 = 23
=> x = 2
4.2x - 3 = 125
=> 4.2x = 125 + 3 = 128
=> 2x = 128 : 4 = 32 = 25
=>x = 5
4x3 +15 = 47
4x3 = 47 - 15
x3 = 32 : 4
x3 = 8
x3 = 23
4.2x - 3 = 125
4.2x = 125 + 3
4.2x = 128
2x = 128 : 4
2x = 32
2x = 25