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4x^2 - 25 - (2x - 5)(2x + 7) = 0
<=>(2x - 5)(2x + 5) - (2x - 5)(2x + 7) = 0
<=>(2x - 5)(2x + 5 - 2x -7) = 0
<=> -2(2x - 5) = 0
<=> -4x + 10 = 0
<=> -4x = -10
<=> x = 5/2
4x^2-25-(2x5-5)(2x+7)=0
4x^2- 25-(2x-5)(2x-7)=0
1, x(2x-7)-4x+14=0 2, x+x^2-x^3-x^4=0
3, 2x^3+3x^2+2x+3=0 4, 4x^2 - 25 - (2x-5)(2x+7)=0
Tìm x biết 2(x+3)-x^2-3x=0
x^3+27+(x+3)(x-9)=0
4x^2-25-(2x-5)(2x+7)=0
8x^3-50x=0
(2x-1)^2-25=0
Tìm x, biết
4x2 - 25 - (2x - 5) (2x+7) = 0
Tìm x biết:
4x2-8x+4=2(1-x)(x+1)
4x2-25-(2x-5)(2x+7)=0
8x2+30x+7=0
x2+3x-18=0
Tìm x:
a) 4x^2 - 25 - ( 2x - 5) .( 2x + 7) = 0
b) x^3 + 27 + ( x+3). ( x -9) = 0
tìm x
\(4x^2-25-\left(2x-5\right)\left(2x+7\right)=0\)
Phân tích đa thức thành nhân tử
a) x³-3x²+3x-1-8y³
b) x⁴-4x³+8x²-16x+16
Giải pt
a) 6(x-3) +(x-1) ²-(x+1) ²=2x
b) (x+4) ²-(x+8) (x-8) =96
c) 4x²-1=(2x+1) (3x-5)
d) 2x²-x=3-6x
e) 2x³+5x²-3x=0
f) x(2x-7) -4x+14=0
g) (2x-5) ²-(x+2) ²=0
h) (3x+1) (7x+3) =(5x-7) (3x+1)
i) x²+10x+25-4x(x+5) =0
k))(4x-5) ²-2(16x²-25) =0
l) (4x+3) ²=4(x²-2x+1)
m) x²-11x+28=0
n) 3x³-3x²-6x=0
o) x²-9x+20=0
